B^2-3=2B

Solution for B^2-3=2B equation:

Simplifying
B2 + -3 = 2B

Reorder the terms:
-3 + B2 = 2B

Solving
-3 + B2 = 2B

Solving for variable 'B'.

Reorder the terms:
-3 + -2B + B2 = 2B + -2B

Combine like terms: 2B + -2B = 0
-3 + -2B + B2 = 0

Factor a trinomial.
(-1 + -1B)(3 + -1B) = 0

Subproblem 1
Set the factor '(-1 + -1B)' equal to zero and attempt to solve:

Simplifying
-1 + -1B = 0

Solving
-1 + -1B = 0

Move all terms containing B to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1B = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1B = 0 + 1
-1B = 0 + 1

Combine like terms: 0 + 1 = 1
-1B = 1

Divide each side by '-1'.
B = -1

Simplifying
B = -1
Subproblem 2
Set the factor '(3 + -1B)' equal to zero and attempt to solve:

Simplifying
3 + -1B = 0

Solving
3 + -1B = 0

Move all terms containing B to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1B = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1B = 0 + -3
-1B = 0 + -3

Combine like terms: 0 + -3 = -3
-1B = -3

Divide each side by '-1'.
B = 3

Simplifying
B = 3
Solution
B = {-1, 3}